5x^2=10+8x

Solution for 5x^2=10+8x equation:

5x^2=10+8x

We move all terms to the left:

5x^2-(10+8x)=0

We add all the numbers together, and all the variables

5x^2-(8x+10)=0

We get rid of parentheses

5x^2-8x-10=0

a = 5; b = -8; c = -10;
Δ = b2-4ac
Δ = -82-4·5·(-10)
Δ = 264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{264}=\sqrt{4*66}=\sqrt{4}*\sqrt{66}=2\sqrt{66}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{66}}{2*5}=\frac{8-2\sqrt{66}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{66}}{2*5}=\frac{8+2\sqrt{66}}{10}
$